bio statistics 1

1.A study of 420 comma 012420012 cell phone users found that 138138 of them developed cancer of the brain or nervous system. Prior to this study of cell phone use the rate of such cancer was found to be
0.03160.0316% for those not using cell phones. Complete parts (a) and (b).
a. Use the sample data to construct a 9090% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system.
nothing %less than0.5070.507
C.Upper H 0H0: pnot equals0.5070.507Upper H 1H1: pequals=0.5070.507
D.Upper H 0H0: pequals=0.5070.507Upper H 1H1: pnot equals0.5070.507
Identify the test statistic for this hypothesis test.
The test statistic for this hypothesis test is
nothing .
(Round to two decimal places as needed.)
Identify the P-value for this hypothesis test.
The P-value for this hypothesis test is
nothing .
(Round to three decimal places as needed.)
Identify the conclusion for this hypothesis test.
A.Fail to rejectFail to reject Upper H 0H0. There is notis not sufficient evidence to warrant rejection of the claim that 50.750.7% of newborn babies are boys.
B. RejectReject Upper H 0H0. There isis sufficient evidence to warrant rejection of the claim that 50.750.7% of newborn babies are boys.
C.RejectReject Upper H 0H0.
There is notis not sufficient evidence to warrant rejection of the claim that 50.750.7%
of newborn babies are boys.
D.Fail to rejectFail to reject Upper H 0H0. There isis sufficient evidence to warrant rejection of the claim that 50.750.7% of newborn babies are boys.Do the results support the belief that
50.750.7% of newborn babies are boys?
A.The results support the belief that 50.750.7% of newborn babies are boys because there was no evidence to show that the belief is untrue.
B.The results support the belief that 50.750.7% of newborn babies are boys because there was sufficient evidence to show that the belief is true.
C.The results do not support the belief that 50.750.7% of newborn babies are boys; the results merely show that there is not strong evidence against the rate of 50.750.7%.
D.The results do not support the belief that 50.750.7% of newborn babies are boys because there was sufficient evidence to show that the belief is untrue.
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8. A group of students estimated the length of one minute without reference to a watch or clock and the times (seconds) are listed below. Use a 0.010.01 significance level to test the claim that these times are from a population with a mean equal to 60 seconds. Does it appear that students are reasonably good at estimating one minute?
76
88
50
72
48
33 66 73 72 54 72 76 101 76 What are the null and alternative hypotheses?
A.Upper H 0H0: mu equals=6060 secondsUpper H 1H1: munot equals6060
seconds
B.Upper H 0H0: mu equals=6060 secondsUpper H 1H1: muless than<6060 seconds C.Upper H 0H0: munot equals6060 secondsUpper H 1H1: muequals=6060 seconds D.Upper H 0H0: muequals=6060 seconds Upper H 1H1: mugreater than>6060
seconds
Determine the test statistic.
nothing
(Round to two decimal places as needed.)
Determine the P-valuenothing
(Round to three decimal places as needed.)
State the final conclusion that addresses the original claim.

Reject
Fail to reject
Upper H 0H0.
There is

sufficient
not sufficient
evidence to conclude that the mean of the population of estimates

is not
is greater than
is less than
6060
seconds. It

appears
does not appear
that as a group the students are reasonably good at estimating one minute.
9. Assume that a simple random sample has been selected from a normally distributed population and test the given claim. Identify the null and alternative hypotheses test statistic P-value and state the final conclusion that addresses the original claim.
A safety administration conducted crash tests of child booster seats for cars. Listed below are results from those tests with the measurements given in hic (standard head injury condition units). The safety requirement is that the hic measurement should be less than 1000 hic. Use a
0.050.05
significance level to test the claim that the sample is from a population with a mean less than 1000 hic. Do the results suggest that all of the child booster seats meet the specified requirement?
717717
588588
10411041
555555
530530
529529
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What are the hypotheses?
A.Upper H 0H0: muequals=10001000 hicUpper H 1H1: mugreater than or equals10001000 hic
B.Upper H 0H0: muless than<10001000 hicUpper H 1H1: mugreater than or equals10001000 hic C.Upper H 0H0: mugreater than>10001000 hicUpper H 1H1: muless than<10001000 hicD.Upper H 0H0: muequals=10001000 hicUpper H 1H1: muless than<10001000 hic Identify the test statistic. tequals=nothing (Round to three decimal places as needed.) Identify the P-value. The P-value is nothing . (Round to four decimal places as needed.) State the final conclusion that addresses the original claim. Reject Fail to reject Upper H 0H0. There is Sufficient insufficient evidence to support the claim that the sample is from a population with a mean less than 1000 hic. What do the results suggest about the child booster seats meeting the specified requirement? A.There is not strong evidence that the mean is less than 1000 hic and one of the booster seats has a measurement that is greater than 1000 hic. B.There is strong evidence that the mean is less than 1000 hic but one of the booster seats has a measurement that is greater than 1000 hic. C.The requirement is met since most sample measurements are less than 1000 hic. D. The results are inconclusive regarding whether one of the booster seats could have a measurement that is greater than 1000 hic. More Less Click to select your answer(s). 0% SCORE: 0 REMAINING:10/10 10. Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea 4040 of the 4747 subjects treated with echinacea developed rhinovirus infections. In a placebo group 7575 of the 9090 subjects developed rhinovirus infections. Use a 0.010.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? A.Upper H 0H0: p 1p1less than or equalsp 2p2 Upper H 1H1: p 1p1not equalsp 2p2 B.Upper H 0H0: p 1p1equals=p 2p2Upper H 1H1: p 1p1greater than>p 2p2
C.Upper H 0H0: p 1p1equals=p 2p2Upper H 1H1: p 1p1not equalsp 2p2
D.Upper H 0H0: p 1p1greater than or equalsp 2p2Upper H 1H1: p 1p1not equalsp 2p2
E.Upper H 0H0: p 1p1not equalsp 2p2Upper H 1H1: p 1p1equals=p 2p2
F.Upper H 0H0: p 1p1equals=p 2p2Upper H 1H1: p 1p1less than

mu 22
D.
Upper H 0H0:
mu 11greater than>mu 22
Upper H 1H1:
mu 11equals=mu 22
E.
Upper H 0H0:
mu 11not equalsmu 22
Upper H 1H1:
mu 11equals=mu 22
F.
Upper H 0H0:
mu 11less than0
B.
Upper H 0H0:
mu Subscript dd not equals0
Upper H 1H1:
mu Subscript dd greater than>0
C.
Upper H 0H0:
mu Subscript dd equals=0
Upper H 1H1:
mu Subscript dd less than<0 D. Upper H 0H0: mu Subscript dd not equals0 Upper H 1H1: mu Subscript dd equals=0 Identify the test statistic. T equals=nothing (Round to two decimal places as needed.) Identify the P-value. P-value equals=nothing (Round to three decimal places as needed.) Since the P-value is greater less than the significance level reject fail to reject Upper H 0H0. There is insufficient sufficient evidence to support the claim that the drug is effective in lowering systolic blood pressure.