How do you name alkanes from Newman projections?

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    To name an alkane from a Newman projection you convert the projection to a line structure; then you write the IUPAC name.
    EXAMPLE:
    Name the alkane shown in the following Newman projection.
    Solution:
    One C atom is at the front of the circle. Another C atom hides behind the circle. You must trace the bonds through the structure.
    Pick the longest chain from one of the three groups attached to the front C atom.
    Since they are all CH groups pick one of them. Label that CH carbon C-1.
    C-1 attaches to C-2 the front carbon.
    C-2 attaches to the other two CH groups and to the hidden C-3. Label the front carbon C-2.
    C-3 attaches to two H atoms and a CHCH group. Pick the longest group (CHCH) to form the rest of the chain.
    Label the CH carbon as C-4.
    Label the CH carbon as C-5.
    You now have the longest chain in the molecule.
    Draw the line structure.
    C-1 = CH
    C-2 = C(CH)
    C-3 = CH
    C-4 = CH
    C-5 = CH
    Your structure should look something like the structure below.
    Write the IUPAC name.
    The alkane is 22-dimethylpentane.

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